Tricky Questions

What is the correct way to check if a key is present in a dictionary?

my_dict = {'name': 'John', 'age': 25}
key_to_check = 'age'

A:

if key_to_check in my_dict.keys():

B:

if key_to_check in my_dict:

C:

if my_dict.contains(key_to_check):

D:

if my_dict.exists(key_to_check):

Answer: B

The correct way to check if a key is present in a dictionary is to use the in keyword directly on the dictionary.

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What will be the output of the following Python code?

x = 5
y = 2

result = x // y

A:

2.5

B:

2

C:

3

D:

2.0

Answer: B

The // operator performs integer division in Python, discarding any remainder. Therefore, 5 // 2 results in 2.

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What is the value of result after executing the following Python code?

my_list = [1, 2, 3, 4, 5]
result = my_list[::2]

A:

[1, 3, 5]

B:

[2, 4]

C:

[5, 3, 1]

D:

[1, 2, 3, 4, 5]

Answer: A

The slicing notation my_list[::2] extracts elements with a step of 2, starting from index 0. Therefore, it includes elements at indices 0, 2, and 4, resulting in the list [1, 3, 5].

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What is the output of the following Python code?

def mystery_function(x):
    return x if x > 0 else mystery_function(-x)

result = mystery_function(-5)
print(result)

A:

-5

B:

5

C:

0

D:

This code will result in an infinite loop.

Answer: B

The mystery_function recursively calls itself with the absolute value of the input until the input is greater than 0. Therefore, mystery_function(-5) returns mystery_function(5), resulting in the output 5.

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Questions for: Tricky Questions