Exercise: Tricky Questions

Questions for: Tricky Questions

What will be the output of the following Python code? 
class MyClass:
    x = 10

obj1 = MyClass()
obj2 = MyClass()
obj1.x += 5
result = obj2.x
print(result)
A:
10
B:
5
C:
15
D:
This code will result in an error.
Answer: A
The code defines a class called MyClass with a class variable x set to 10.
obj1 and obj2 are both instances of the MyClass class.
When obj1.x += 5 is executed, it modifies the x attribute of obj1 by adding 5 to its current value. Since obj1 does not have its own x attribute, it accesses the class variable x and performs the addition. As a result, obj1.x becomes 15.
When result = obj2.x is executed, it assigns the value of obj2.x to the variable result. Since obj2 does not have its own x attribute, it also accesses the class variable x. Therefore, result is 10.
Finally, 10 is printed to the console as the output of the code.
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What is the output of the following Python code? 
x = [1, 2, 3]
y = x
x += [4, 5]
print(y)
A:
[1, 2, 3]
B:
[1, 2, 3, 4, 5]
C:
[1, 2, 3, 4, 5] (but with a warning)
D:
This code will result in an error.
Answer: B
The += operator modifies the list in-place, and y reflects this change.
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Consider the following Python code: 
def my_generator():
    for i in range(5):
        yield i * 2

result = list(my_generator())
print(result)
What will be the output of this code?
A:
[0, 2, 4, 6, 8]
B:
[0, 1, 4, 9, 16]
C:
[0, 2, 4, 8, 16]
D:
This code will result in an error.
Answer: A
The generator yields values multiplied by 2 in the range [0, 2, 4, 6, 8].
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What will be the output of the following Python code? 
class Parent:
    def __init__(self, x):
        self.x = x

class Child(Parent):
    def __init__(self, x, y):
        super().__init__(x)
        self.y = y

obj = Child(10, 20)
result = obj.x * obj.y
print(result)
A:
30
B:
200
C:
This code will result in an error.
D:
10
Answer: B
The child class Child initializes x and y, and the result is the product of these attributes.
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What is the output of the following Python code? 
a = [1, 2, 3]
b = a
a = a + [4, 5]
print(b)
A:
[1, 2, 3]
B:
[1, 2, 3, 4, 5]
C:
This code will result in an error.
D:
[1, 2, 3, 4, 5] (but with a warning)
Answer: A
The concatenation creates a new list, and b still refers to the original list.
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