Questions for: Time And Distance
How much time did X take to reach the destination? | |
I. | The ratio between the speed of X and Y is 3 : 4. |
II. | Y takes 36 minutes to reach the same destination. |
Since ratio of speed of X : Y is 3 : 4, then ratio of time will be 4 : 3.
I. If Y takes 3 min, then X takes 4 min.
| II. If Y takes 36 min, then X takes | ![]() |
4 | x 36 | min |
= 48 min. |
| 3 |
Thus, I and II together give the answer.
Correct answer is (E).
Two cars pass each other in opposite direction. How long would they take to be 500 km apart? | |
I. | The sum of their speeds is 135 km/hr. |
II. | The difference of their speed is 25 km/hr. |
I gives, relative speed = 135 km/hr.
Time taken = |
500 | hrs. |
| 135 |
II does not give the relative speed.
I alone gives the answer and II is irrelevant.
Correct answer is (A).
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The towns A, B and C are on a straight line. Town C is between A and B. The distance from A to B is 100 km. How far is A from C? | |
I. | The distance from A to B is 25% more than the distance from C to B. |
II. |
The distance from A to C is |
.__________.______________________________________. A x C (100 - x) B
Let AC = x km. Then, CB = (100 -x) km.
I. AB = 125% of CB
100 = |
125 | x (100 - x) |
| 100 |
100 - x = |
100 x 100 | = 80 |
| 125 |
x = 20 km.
AC = 20 km.
Thus, I alone gives the answer.
| II. AC = | 1 | CB |
| 4 |
x = |
1 | (100 - x) |
| 4 |
5x = 100
x = 20.
AC = 20 km.
Thus, II alone gives the answer.
Correct answer is (C).
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Two towns are connected by railway. Can you find the distance between them? | |
I. | The speed of the mail train is 12 km/hr more than that of an express train. |
II. | A mail train takes 40 minutes less than an express train to cover the distance. |
Let the distance between the two stations be x km.
I. Then, speed of the mail train = (y + 12) km/hr.
| II. | x | - | x | = | 40 | . |
| y | (y + 12) | 60 |
Thus, even I and II together do not give x.
Correct answer is (D).
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| 36 | 2 |
| 3 |
| 37 | 1 |
| 2 |
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 | 2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
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min
of the distance C to B.
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