Questions for: Problems On Numbers
What is the two-digit number? | |
I. | Sum of the digits is 7. |
II. | Difference between the number and the number obtained by interchanging the digits is 9. |
III. | Digit in the ten's place is bigger than the digit in the unit's place by 1. |
Let the tens and units digit be x and y respectively.
I. x + y = 7.
II. (10x + y) - (10y + x) = 9
x - y = 1.
III. x - y = 1.
Thus, I and II as well as I and III give the answer.
Correct answer is (E).
What is the two-digit number? | |
I. | The difference between the two-digit number and the number formed by interchanging the digits is 27. |
II. | The difference between the two digits is 3. |
III. | The digit at unit's place is less than that at ten's place by 3. |
Let the tens and units digit be x and y respectively.
I. (10x + y) - (10y + x)
x - y = 3.
II. x - y = 3.
III. x - y = 3.
Thus, even all the given three statements together do not give the answer.
Correct answer is (E).
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What is the two-digit number whose first digit is a and the second digit is b?. The number is greater than 9. | |
I. | The number is multiple of 51. |
II. | The sum of the digits a and b is 6. |
From statement I:
A two digit number, greater than 9 and multiple of 51 should be 51 itself.
Because, 2 x 51 = 102 (3 digit number). Therefore, I alone sufficient to answer.
From statement II:
A two digit number, greater than 9 and sum of the digit is 6.
It can be 15, 24, 33, 42, 51. So we cannot determine the required answer from the statement II alone.
Thus, I alone give the answer while II alone not sufficient to answer.
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What is the two-digit number? | |
I. | The difference between the two digits is 9. |
II. | The sum of the digits is equal to the difference between the two digits. |
Let the tens and unit digits be x and y respectively. Then,
I. x - y = 9.
II. x + y = x - y.
From I and II, we get x - y = 9 and x + y = 9.
On solving, we get x = 9 and y = 0.
Required number is 90.
Thus, both I and II are needed to get the answer.
Correct answer is (E).
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What is the number? | |
I. | The sum of the two digits is 8. The ratio of the two digits is 1 : 3. |
II. | The product of the two digit of a number is 12. The quotient of two digits is 3. |
Let the tens and units digit be x and y respectively. Then,
| I. x + y = 8 and | x | = | 1 |
| y | 3 |
I gives, 4y = 24
y = 6.
So, x + 6 = 8
x = 2.
| II. xy = 12 and | x | = | 3 |
| y | 1 |
II gives, x2 = 36
x = 6.
So, 3y = 6
y = 2.
Therefore, Either I or II alone sufficient to answer.
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Discuss About this Question.