Questions for: Problems On Numbers
| Let the ten's and unit digit be x and | 8 | respectively. |
| x |
| Then, | ![]() |
10x + | 8 | ![]() |
+ 18 = 10 x | 8 | + x |
| x | x |
10x2 + 8 + 18x = 80 + x2
9x2 + 18x - 72 = 0
x2 + 2x - 8 = 0
(x + 4)(x - 2) = 0
x = 2.
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) - (2x - x) = 2x = 8.
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Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (10y + x) = 36
9(x - y) = 36
x - y = 4.
Video Explanation: https://youtu.be/7QOJjAmGVx0
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Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
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Let the number be x.
| Then, | 1 | of | 1 | of x = 15 x = 15 x 3 x 4 = 180. |
| 3 | 4 |
| So, required number = | ![]() |
3 | x 180 | ![]() |
= 54. |
| 10 |
Video Explanation: https://youtu.be/z49OUnzTnwY
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Discuss About this Question.