Internal Forces

The axial forces act on the shaft as shown. Determine the internal axial force at points A and B.

A:

A_A = 0, A_B = 10 lb C

B:

A_A = 0, A_B = 10 lb T

C:

A_A = 10 lb C, A_B = 0

D:

A_A = 10 lb T, A_B = 0

Answer: D

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A force of 500 N acts at the top of the two-member frame. If the members are in smooth contact with one another at A, B, and C with no fasteners, determine the shear force developed at a horizontal section through point D of the support. Also, what are the axial force, shear force and moment at point E?

A:

V_D = 250 N, A_E = 250 N, V_E = 333 N, M_E = 316 N-m

B:

V_D = 333 N, A_E = 333 N, V_E = 250 N, M_E = 267 N-m

C:

V_D = 333 N, A_E = 333 N, V_E = 250 N, M_E = 200 N-m

D:

V_D = 250 N, A_E = 250 N, V_E = 333 N, M_E = 267 N-m

Answer: B

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Determine the internal axial force, shear force, and moment at point E of the oleo strut AB of the aircraft landing gear.

A:

A_E = 9.33 kip C, V_E = 8.00 kip, M_E = 80.0 kip-in.

B:

A_E = 11.11 kip T, V_E = 6.67 kip, M_E = 66.7 kip-in.

C:

A_E = 9.33 kip T, V_E = 8.00 kip, M_E = 80.0 kip-in.

D:

A_E = 11.11 kip C, V_E = 6.67 kip, M_E = 66.7 kip-in.

Answer: D

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The work platform supports an 80-kg man having a mass center at G. Determine the axial force, shear force, and bending moment at point E of the telescopic column AB due to the load of the man only.

A:

A_E = 785 N C, V_E = 0, M_E = 785 N-m

B:

A_E = 785 N C, V_E = 392 N, M_E = 0

C:

A_E = 785 N T, V_E = 392 N, M_E = 0

D:

A_E = 785 N T, V_E = 0, M_E = 785 N-m

Answer: A

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Determine the internal axial force, shear force, and moment at point F of the frame.

A:

A_F = 0, V_F = 750 lb, M_F = 750 lb-ft

B:

A_F = 1500 lb, V_F = 0, M_F = 4500 lb-ft

C:

A_F = 0, V_F = 1500 lb, M_F = 4500 lb-ft

D:

A_F = 750 lb, V_F = 0, M_F = 750 lb-ft

Answer: A

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Questions for: Internal Forces