Exercise: Force Vectors

Questions for: Force Vectors

Determine the design angle for connecting member A to the plate if the resultant force is to be directed vercially upward. Also, what is the magnitude of the resultant?

A:
R = 400 N, = 53.5°
B:
R = 250 N, = 30.0°
C:
R = 300 N, = 36.9°
D:
R = 640 N, = 38.6°
Answer: C
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Determine the magnitude and direction angles of F2, so that the resultant of the two forces acts upward along the z axis of the pole and has a magnitude of 275 N.

A:
F2 = 246 N, = 54.9°, = 114.0°, = 44.7°
B:
F2 = 200 N, = 45.0°, = -60.0°, = 29.0°
C:
F2 = 200 N, = 45.0°, = 120.0°, = 29.0°
D:
F2 = 246 N, = 54.9°, = 66.0°, = 44.7°
Answer: A
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Express each force in Cartesian vector form.

A:
F1 = (2.50 i + 3.54 j + 2.50 k) kN, F2 = -2 j kN
B:
F1 = (4.33 i + 3.54 j + 4.33 k) kN, F2 = -2 j kN
C:
F1 = (2.17 i + 3.75 j + 4.33 k) kN, F2 = -2 j kN
D:
F1 = (4.33 i + 3.75 j + 2.17 k) kN, F2 = -2 j kN
Answer: A
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Determine the magnitude and direction of F so that this force has components of 40 lb acting from A toward B and 60lb acting from A toward C on the frame.

A:
F = 44.7 lb, = 22.9°
B:
F = 80.3 lb, = 46.2°
C:
F = 62.9 lb, = 37.1°
D:
F = 72.1 lb, = 56.3°
Answer: B
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Determine the design angle ( <90°) bretween the two struts so that the 500-lb horizontal force has a component of 600lb directed from A toward C. That is the component of force acting along member AB?

A:
FAB = 321 lb, = 40.0°
B:
FAB = 383 lb, = 36.9°
C:
FAB = 171.1 lb, = 20.0°
D:
FAB = 215 lb, = 52.7°
Answer: D
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