Exercise: Force System Resultants

Questions for: Force System Resultants

Replace the force and couple system by an equivalent single force and couple acting at point P.

A:
F = (-8.66i-15.00j) N, M = 50.0 N-m
B:
F = (8.66i-15.00j) N, M = 42.0 N-m
C:
F = (8.66i-15.00j) N, M = 50.0 N-m
D:
F = (-8.66i-15.00j) N, M = 42.0 N-m
Answer: B
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Replace the two forces acting on the tree branches by an equivalent force and couple moment acting at point O.

A:
R = (60i+198j-36k) N, M = (747i+18j-924k) N-m
B:
R = (60i+18j-324k) N, M = (747i+18j-924k) N-m
C:
R = (60i+198j-36k) N, M = (360i+1260j-414k) N-m
D:
R = (60i+18j-324k) N, M = (360i+1260j-414k) N-m
Answer: B
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The distributed loadings of soil pressure on the sides and bottom of a spread footing are shown. Simplify this system to a single resultant force and couple moment acting at A. What is the resultant force F and the couple moment M?

A:
F = (72i + 125j)N, M = 83.5 N-m CCW
B:
F = (144i + 125j)N, M = 135.7 N-m CCW
C:
F = (144i + 125j)N, M = 83.5 N-m CCW
D:
F = (72i + 125j)N, M = 102.1 N-m CCW
Answer: D
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Determine the moment of force F2 about point A on the beam.

A:
M2 = 800 ft-lb
B:
M2 = 50 ft-lb
C:
M2 = 600 ft-lb
D:
M2 = 37.5 ft-lb
Answer: C
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Determine the direction (0° 180°) of the 30-lb force F so that the moment of F about point A has the maximum magnitude.

A:
= 36.9°
B:
= 53.1°
C:
= 127.0°
D:
= 90.0°
Answer: A
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