Question 1

Will the printf() statement print the same values for any values of a?

#include<stdio.h>
int main()
{
    float a;
    scanf("%f", &a);
    printf("%f\n", a+a+a);
    printf("%f\n", 3*a);
    return 0;
}

Answer

Answer: A

No answer description is available. Let's discuss.

Question 2

Point out the error in the following program.

#include<stdio.h>
int main()
{
    struct emp
    {
        char name[20];
        float sal;
    };
    struct emp e[10];
    int i;
    for(i=0; i<=9; i++)
        scanf("%s %f", e[i].name, &e[i].sal);
    return 0;
}

Answer

Answer: B

Compile and Run the above program in Turbo C:

C:\>myprogram.exe
Sundar
2555.50
scanf : floating point formats not linked
Abnormal program termination

The program terminates abnormally at the time of entering the float value for e[i].sal.

Solution:

Just add the following function in your program. It will force the compiler to include required libraries for handling floating point linkages.

static void force_fpf() /* A dummy function */
{
    float x, *y; /* Just declares two variables */
    y = &x      /* Forces linkage of FP formats */
    x = *y;      /* Suppress warning message about x */
}

Question 3

What will be the output of the program?

#include<stdio.h>
int main()
{
    float d=2.25;
    printf("%e,", d);
    printf("%f,", d);
    printf("%g,", d);
    printf("%lf", d);
    return 0;
}

Answer

Answer: C

printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 2.25 as 2.250000e⁺⁰⁰⁰.

printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 2.25 as 2.250000.

printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 2.25 as 2.25.

printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints the 2.25 as 2.250000.

Question 4

What will be the output of the program?

#include<stdio.h>
#include<math.h>
int main()
{
    float n=1.54;
    printf("%f, %f\n", ceil(n), floor(n));
    return 0;
}

Answer

Answer: A

ceil(x) round up the given value. It finds the smallest integer not < x.
floor(x) round down the given value. It finds the smallest integer not > x.

printf("%f, %f\n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2 and floor(1.54) round down the 1.54 to 1.

In the printf("%f, %f\n", ceil(n), floor(n)); statement, the format specifier "%f %f" tells output to be float value. Hence it prints 2.000000 and 1.000000.

Question 5

What will be the output of the program?

#include<stdio.h>
int main()
{
    float a=0.7;
    if(a < 0.7f)
        printf("C\n");
    else
        printf("C++\n");
    return 0;
}

Answer

Answer: B

if(a < 0.7f) here a is a float variable and 0.7f is a float constant. The float variable a is not less than 0.7f float constant. But both are equal. Hence the if condition is failed and it goes to else it prints 'C++'
Example:

#include<stdio.h>
int main()
{
    float a=0.7;
    printf("%.10f %.10f\n",0.7f, a);
    return 0;
}

Output:
0.6999999881 0.6999999881

Questions for: Floating Point Issues