Exercise: Center Of Gravity And Centroid
Questions for: Center Of Gravity And Centroid
Locate the centroid of the exparabolic segment of area.
A: 
= -4a/5, 
= -b/4
= -4a/5, = -b/4B: = -3a/4, = -3b/10
= -3a/4, = -3b/10C: = -2a/3, = -b/3
= -2a/3, = -b/3D: = -5a/7, = -3b/8
= -5a/7, = -3b/8
Answer: B
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Locate the center of gravity of the homogeneous "bell-shaped" volume formed by revolving the shaded area about the y axis.
A: = 3.33 ft
= 3.33 ftB: = 2.80 ft
= 2.80 ftC: = 3.20 ft
= 3.20 ftD: = 3.00 ft
= 3.00 ft
Answer: A
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Locate the center of gravity of the volume generated by revolving the shaded area about the z axis. The material is homogeneous.
A: 
= 2.80 ft
= 2.80 ftB: = 2.50 ft
= 2.50 ftC: = 2.67 ft
= 2.67 ftD: = 3.00 ft
= 3.00 ft
Answer: C
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The truss is made from seven members, each having a mass of 6 kg/m. Locate the position (,) of the center of mass. Neglect the mass of the gusset plates at the joints.
A: = 2.36 m, = 1.286 m
= 2.36 m, = 1.286 mB: = 2.33 m, = 1.333 m
= 2.33 m, = 1.333 mC: = 2.43 m, = 1.308 m
= 2.43 m, = 1.308 mD: = 2.79 m, = 1.757 m
= 2.79 m, = 1.757 m
Answer: C
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Determine the distance to the centroidal axis of the beam's cross-sectional area.
A: = 112.3 mm
= 112.3 mmB: = 125.0 mm
= 125.0 mmC: = 100.0 mm
= 100.0 mmD: = 91.7 mm
= 91.7 mm
Answer: D
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