Exercise: Table Charts

Questions for: Table Charts

What is the pooled average of the total number of employees of all categories in the year 1997?
A:
1325
B:
1195
C:
1265
D:
1235
Answer: B

Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.
Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.
Operators = (880 + 256 + 240) - (104 + 120) = 1152.
Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.
Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore Pooled average of all the five categories of employees working in the Company in 1997

    = 1 x (1007 + 1464 + 1152 + 1380 + 972)
5

    = 1 x (5975)
5

    = 1195.

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For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?
A:
Managers
B:
Technicians
C:
Operators
D:
Accountants
Answer: A

Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)
= 1252.

Therefore Percentage increase in the number of Managers

    = [ (1252 - 760) x 100 ] % = 64.74%.
760

Number of Technicians working in the Company:

In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) -

   (120 + 128 + 96 + 100 + 112)
= 1936.

Therefore Percentage increase in the number of Technicians

    = [ (1936 - 1200) x 100 ] % = 61.33%.
1200

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) -

    (104 + 120 + 100 + 112 + 144)
= 1444.

Therefore Percentage increase in the number of Operators

    = [ (1444 - 880) x 100 ] % = 64.09%.
880

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) -

    (100 + 104 + 96 + 88 + 92)
= 1884.

Therefore Percentage increase in the number of Accountants

    = [ (1884 - 1160) x 100 ] % = 62.41%.
1160

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) -

    (96 + 88 + 80 + 120 + 104)
= 1288.

Therefore Percentage increase in the number of Peons

    = [ (1288 - 820) x 100 ] % = 57.07%.
820

Clearly, the percentage increase is maximum in case of Managers.

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What was the total number of Peons working in the Company in the year 1999?
A:
1312
B:
1192
C:
1088
D:
968
Answer: B

Total number of Peons working in the Company in 1999

    = (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

    = 1192.

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What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?
A:
128
B:
112
C:
96
D:
88
Answer: D

Required difference

    = (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

    = 88.

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Which section has the minimum failure rate in half yearly examination?
A:
A section
B:
B section
C:
C section
D:
D section
Answer: D

Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams)

        + (Number of students failed in half-yearly but passed in Annual exams)

   ] in that section

Therefore Failure rate in half-yearly exams in Section A

    = [ Number of students of Section A failed in half-yearly x 100 ] %
Total number of students in Section A

    = [ (28 + 14) x 100 ] %
(28 + 14 + 6 + 64)

    = [ 42 x 100 ] %
112

    = 37.5%.

Similarly, failure rate in half-yearly exams in:

Section B [ (23 + 12) x 100 ] % = [ 35 x 100 ] % = 32.71%.
(23 + 12 + 17 + 55) 107

Section C [ (17 + 8) x 100 ] % = [ 25 x 100 ] % = 31.25%.
(17 + 8 + 9 + 46) 80

Section D [ (27 + 13) x 100 ] % = [ 40 x 100 ] % = 30.53%.
(27 + 13 + 15 + 76) 131

Clearly, the failure rate is minimum for Section D.

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