#include<stdio.h>
int main()
{
union a
{
int i;
char ch[2];
};
union a u;
u.ch[0]=3;
u.ch[1]=2;
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
return 0;
}
A:
3, 2, 515
B:
515, 2, 3
C:
3, 2, 5
D:
515, 515, 4
Answer:A
The system will allocate 2 bytes for the union.
The statements u.ch[0]=3; u.ch[1]=2; store data in memory as given below.
Discuss About this Question.
What is the similarity between a structure, union and enumeration?
Discuss About this Question.