Exercise: Strings

Questions for: Strings

What will be the output of the program ? 
#include<stdio.h>

int main()
{
    static char mess[6][30] = {"Don't walk in front of me...", 
                               "I may not follow;", 
                               "Don't walk behind me...", 
                               "Just walk beside me...", 
                               "And be my friend." };

    printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9));
    return 0;
}
A:
t, t
B:
k, k
C:
n, k
D:
m, f
Answer: B
No answer description is available. Let's discuss.
📖
📝
💬
👁️
If the size of pointer is 32 bits What will be the output of the program ? 
#include<stdio.h>

int main()
{
    char a[] = "Visual C++";
    char *b = "Visual C++";
    printf("%d, %d\n", sizeof(a), sizeof(b));
    printf("%d, %d", sizeof(*a), sizeof(*b));
    return 0;
}
A:
10, 2
2, 2
B:
10, 4
1, 2
C:
11, 4
1, 1
D:
12, 2
2, 2
Answer: C
No answer description is available. Let's discuss.
📖
📝
💬
👁️
If char=1, int=4, and float=4 bytes size, What will be the output of the program ? 
#include<stdio.h>

int main()
{
    char ch = 'A';
    printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));
    return 0;
}
A:
1, 2, 4
B:
1, 4, 4
C:
2, 2, 4
D:
2, 4, 8
Answer: B

Step 1: char ch = 'A'; The variable ch is declared as an character type and initialized with value 'A'.

Step 2:

printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14));

The sizeof function returns the size of the given expression.

sizeof(ch) becomes sizeof(char). The size of char is 1 byte.

sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question).

sizeof(3.14f). The size of float is 4 bytes.

Hence the output of the program is 1, 4, 4

📖
📝
💬
👁️
What will be the output of the program ? 
#include<stdio.h>

int main()
{
    int i;
    char a[] = "\0";
    if(printf("%s", a))
        printf("The string is empty\n");
    else
        printf("The string is not empty\n");
    return 0;
}
A:
The string is empty
B:
The string is not empty
C:
No output
D:
0
Answer: B

The function printf() returns the number of charecters printed on the console.

Step 1: char a[] = "\0"; The variable a is declared as an array of characters and it initialized with "\0". It denotes that the string is empty.

Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns '0'(zero). Hence the if condition is failed.

In the else part it prints "The string is not empty".

📖
📝
💬
👁️
What will be the output of the program in 16-bit platform (Turbo C under DOS) ? 
#include<stdio.h>

int main()
{
    printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
    return 0;
}
A:
8, 1, 4
B:
4, 2, 8
C:
4, 2, 4
D:
10, 3, 4
Answer: B

Step 1:

printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));

The sizeof function returns the size of the given expression.

sizeof(3.0f) is a floating point constant. The size of float is 4 bytes

sizeof('3') It converts '3' in to ASCII value.. The size of int is 2 bytes

sizeof(3.0) is a double constant. The size of double is 8 bytes

Hence the output of the program is 4,2,8

Note: The above program may produce different output in other platform due to the platform dependency of C compiler.

In Turbo C, 4 2 8. But in GCC, the output will be 4 4 8.

📖
📝
💬
👁️
Ad Slot (Above Pagination)
Quiz