Exercise: Probability
Questions for: Probability
Two dice are tossed. The probability that the total score is a prime number is:
A:
| 1 |
| 6 |
B:
| 5 |
| 12 |
C:
| 1 |
| 2 |
D:
| 7 |
| 9 |
Answer: B
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
| Then E | = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } |
n(E) = 15.
P(E) = |
n(E) | = | 15 | = | 5 | . |
| n(S) | 36 | 12 |
From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
A:
| 1 |
| 15 |
B:
| 25 |
| 57 |
C:
| 35 |
| 256 |
D:
| 1 |
| 221 |
Answer: D
Let S be the sample space.
| Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
| (2 x 1) |
Let E = event of getting 2 kings out of 4.
n(E) = 4C2 = |
(4 x 3) | = 6. |
| (2 x 1) |
P(E) = |
n(E) | = | 6 | = | 1 | . |
| n(S) | 1326 | 221 |
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In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
A:
| 1 |
| 10 |
B:
| 2 |
| 5 |
C:
| 2 |
| 7 |
D:
| 5 |
| 7 |
Answer: C
| P (getting a prize) = | 10 | = | 10 | = | 2 | . |
| (10 + 25) | 35 | 7 |
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In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
A:
| 21 |
| 46 |
B:
| 25 |
| 117 |
C:
| 1 |
| 50 |
D:
| 3 |
| 25 |
Answer: A
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
| Then, n(S) | = Number ways of selecting 3 students out of 25 | |||
| = 25C3 ` | ||||
|
||||
| = 2300. |
| n(E) | = (10C1 x 15C2) | ||||||
|
|||||||
| = 1050. |
P(E) = |
n(E) | = | 1050 | = | 21 | . |
| n(S) | 2300 | 46 |
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Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
A:
| 1 |
| 2 |
B:
| 3 |
| 4 |
C:
| 3 |
| 8 |
D:
| 5 |
| 16 |
Answer: B
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
| Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
P(E) = |
n(E) | = | 27 | = | 3 | . |
| n(S) | 36 | 4 |
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