Exercise: Networks Analysis And Synthesis

Questions for: Networks Analysis And Synthesis

Two voltages are v1= 100 sin (ωt + 15°) and v2 = 60 cosωt, then
A:
v1 is leading v2 by 15°
B:
v1 is leading v2 by 75°
C:
v2 is leading v1 by 75°
D:
v2 is lagging v1 by 15°
Answer: C

v1 = 100 sin (ωt + 15°) and v2 = 60 cos ωt = 60 sin (ωt + 90°). Hence, v2 is leading v1 by (90 - 15) = 75°.

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S is closed for a long time and steady state is reached. S is opened at t(0-). The voltage marked V is V0 at t = 0+ and Vf at t = ∞. Then value of V0 and Vf are respectively
A:
8, 8
B:
0, 1
C:
4, 0
D:
4, 8
Answer: D

For Thevenin Equivalent Resistance, v = 0, I = 0

.

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Current having waveform in figure flows through 10 Ω resistance. Average power is
A:
1000 W
B:
500 W
C:
333.3 W
D:
250 W
Answer: C

RMS current = = 5.773 A, P = I2R = 333.3 W.

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For a high pass filter attenuation = 0 at f = 0.
A:
True
B:
False
C:
D:
Answer: B

Attenuation is infinite at f = 0 for high pass filter.

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In the circuit of figure the current through L at t = ∞ is
A:
0 A
B:
10 A
C:
6.67 A
D:
5.1 A
Answer: B

At t = ∞ inductance behaves as short-circuit.

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