Exercise: Networks Analysis And Synthesis

Questions for: Networks Analysis And Synthesis

A coil of resistance R and inductance L is connected in series with 5 μF capacitor. The source frequency is equal to resonance frequency and circuit current is 0.5 A. Another 5 F capacitor is connected in parallel with the above capacitor. The circuit current will be
A:
0.5 A
B:
more than 0.5 A
C:
less than 0.5 A
D:
0.5 A or less
Answer: C

Since C increases, the circuit will not be in resonance. Therefore, current decreases (In series resonant circuit current is maximum at resonance).

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A certain network has two ideal voltages sources and a large number of ideal resistances. The power consumed in one of the resistances is 4 W when either of two sources is active and the other source is active and the other source is short circuited. When both sources is short circuited.When both sources are active, the power consumed in the same resistor would be
A:
zero or 16 W
B:
4 W or 8 W
C:
zero or 8 W
D:
8 W or 16 W
Answer: A

If currents of both sources add, total current would be twice and power is four time, i.e., 16 W. If currents subtract, net current and power are zero.

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For the two port of figure, z11 is
A:
26/7 Ω
B:
10/3 Ω
C:
6 Ω
D:
2 Ω
Answer: A

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An RL series circuit is initially relaxed. A step voltage E is applied. If t is time constant, voltage across R and L will be equal at t =
A:
t ln 2
B:
C:
D:
Answer: B

vR = E(1 - e-t/t) and vL = E e-t/t or 1 - e-t/t = e-t/t. This happens at t = t in 2.

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Assertion (A): The Laplace transform of a ramp is 1/s2.

Reason (R): The integral of a unit step function gives an impulse function.

A:
Both A and R are true and R is correct explanation of A
B:
Both A and R are true and R is not the correct explanation of A
C:
A is true but R is false
D:
A is false but R is true
Answer: C

Integral of unit impulse gives unit step function.

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