Two capacitors of 16 μF each are connected in series. Another capacitor of 16 μF is connected in parallel with this combination. The total capacitance will be
A:
48 μF
B:
32 μF
C:
24 μF
D:
Answer:C
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In the circuit of figure, the current through battery E3 is
A:
4 A charging
B:
4 A discharging
C:
4 A charging or discharging depending on value of E3
D:
4 A charging or discharging depending on values of E1, E2, E3
Answer:A
4 A current is flowing into the battery. Therefore, it is charging current.
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The internal impedance of a source is 3 + j 7 Ω. For maximum power transfer, load impedance should be
A:
3 + j 7 Ω
B:
3 - j 7 Ω
C:
7 + j 3 Ω
D:
7 - j 3 Ω
Answer:B
Load impedance should be conjugate of source impedance.
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In figure readings of the two voltmeters should be
A:
100 V on each meter
B:
200 V on each meter
C:
150 V on V1 and 50 V on V2
D:
50 V on V1 and 150 V on V2
Answer:B
Both voltmeter connected in parallel, hence read same voltage as applied.
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The internal impedance of a source is 3 + j 4 Ω. It is desired to supply maximum power to a resistive load. The load resistance should be
A:
3 Ω
B:
4 Ω
C:
7 Ω
D:
5 Ω
Answer:D
RL = 32 + 42.
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