Consider the following expressions in Java int a, b, c, a = 40; b = a++ ; c = ++a ; Now the values of a, b, c are
A:
42, 40, 42 respectively
B:
42, 42, 42 respectively
C:
40, 42, 42 respectively
D:
40, 40, 42 respectively
Answer:A
The steps are : a is given the value 40, b is given the value of a before it is incremented (i.e., 40) and a is incremented to 41, a is incremented to 42 and c is given this value. Thus the result is 42, 40, 42.
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In 8085 eight address and data buses are multiplexed.
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