Exercise: Foundational Math
Questions for: Arithmetical Ratios
A collection of vintage coins consists only of copper coins and silver coins. The ratio of copper coins to silver coins is 7:4. If there are 27 more copper coins than silver coins, what is the total number of coins in the collection?
A: 63
B: 99
C: 108
D: 121
Answer: B
1. Let the number of copper coins be 7x and the number of silver coins be 4x, where x is a common multiplier.
2. The difference between the number of copper coins and silver coins is given as 27.
3. Set up the equation: 7x - 4x = 27.
4. Simplify the equation: 3x = 27.
5. Solve for x: x = 27 / 3 = 9.
6. The total number of coins is the sum of copper and silver coins, which is 7x + 4x = 11x.
7. Substitute the value of x back into the total: Total coins = 11 * 9 = 99.
Why others are wrong:
A — This represents only the number of copper coins (7 * 9 = 63).
B — Correct.
C — This error could arise if one correctly finds x=9 but incorrectly assumes the total ratio parts are 12 (e.g., 7+5 instead of 7+4), leading to 9 * 12 = 108.
D — This error could arise if one correctly identifies the total ratio parts as 11 but incorrectly assumes the value of x is also 11 (instead of 9), leading to 11 * 11 = 121.
A painter mixes blue and yellow paint. Initially, the ratio of blue paint to yellow paint is 5:3. To adjust the shade, the painter adds 4 more parts of yellow paint to the mixture, without adding any more blue paint.
What is the new ratio of blue paint to yellow paint in the mixture?
A: 5:7
B: 5:4
C: 9:3
D: 9:7
Answer: A
The initial ratio of blue paint to yellow paint is 5:3.
This means there are 5 parts of blue paint and 3 parts of yellow paint.
The painter adds 4 more parts of yellow paint.
The amount of blue paint remains unchanged at 5 parts.
The amount of yellow paint becomes 3 (initial parts) + 4 (added parts) = 7 parts.
The new ratio of blue paint to yellow paint is therefore 5:7.
Why others are wrong:
A — This option correctly represents the new ratio after adding yellow paint.
B — This option incorrectly assumes the yellow paint quantity changed from 3 parts to 4 parts, rather than increasing by 4 parts.
C — This option incorrectly adds 4 parts to the blue paint (5+4=9), or implies a miscalculation for both parts.
D — This option incorrectly adds 4 parts to *both* the blue paint (5+4=9) and the yellow paint (3+4=7), which is not stated in the scenario.
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A local library received a total donation of $4800 from three community groups: the Reading Club, the Volunteer Association, and the Friends of the Library. The amounts donated by these groups were in the ratio 3:5:4, respectively.
How much more did the Volunteer Association donate than the Reading Club?
A: $400
B: $800
C: $1200
D: $2000
Answer: B
1. First, sum the parts of the given ratio: 3 + 5 + 4 = 12 parts.
2. Next, determine the value of one ratio part by dividing the total donation by the total number of parts: $4800 / 12 = $400 per part.
3. Calculate the donation from the Volunteer Association (5 parts): 5 * $400 = $2000.
4. Calculate the donation from the Reading Club (3 parts): 3 * $400 = $1200.
5. Finally, find the difference between their donations: $2000 - $1200 = $800.
Why others are wrong:
A — This is the calculated value of a single ratio part, not the required difference.
C — This is the amount donated by the Reading Club, not the difference asked in the question.
D — This is the amount donated by the Volunteer Association, not the difference asked in the question.
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A school's sports committee is distributing medals for three categories: Gold, Silver, and Bronze. The ratio of Gold to Silver medals is set at 2:3, and the ratio of Silver to Bronze medals is 4:5.
If the committee plans to award a total of 105 medals, how many Silver medals will be distributed?
A: 21
B: 24
C: 36
D: 45
Answer: C
1. Identify the given ratios: Gold:Silver = 2:3 and Silver:Bronze = 4:5.
2. Combine the ratios to find a common ratio for Gold:Silver:Bronze. The 'Silver' part is common to both ratios (3 and 4). Find the Least Common Multiple (LCM) of 3 and 4, which is 12.
3. Adjust the first ratio to have 12 for Silver: G:S = (2 * 4) : (3 * 4) = 8:12.
4. Adjust the second ratio to have 12 for Silver: S:B = (4 * 3) : (5 * 3) = 12:15.
5. The combined ratio is G:S:B = 8:12:15.
6. Calculate the total number of parts in the combined ratio: 8 + 12 + 15 = 35 parts.
7. Determine the value of one part: Total medals / Total parts = 105 / 35 = 3 medals per part.
8. Calculate the number of Silver medals: Silver's ratio part * Value per part = 12 * 3 = 36.
Why others are wrong:
A — This result (21) is obtained by incorrectly summing the initial silver ratio parts (3+4=7) and then calculating (7/35) * 105.
B — This result (24) represents the number of Gold medals (8 parts * 3).
D — This result (45) represents the number of Bronze medals (15 parts * 3).
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A philanthropic organization allocated a total of $8400 to be distributed between two charitable trusts, Trust X and Trust Y. The distribution was determined by a ratio of 3:5, with Trust X receiving the smaller proportion.
How much money did Trust Y receive?
A: $1050
B: $3150
C: $4200
D: $5250
Answer: D
The total ratio parts are 3 (for Trust X) + 5 (for Trust Y) = 8 parts.
Each ratio part is worth the total amount divided by the total parts: $8400 / 8 = $1050.
Trust Y receives 5 parts of the distribution.
Therefore, Trust Y receives 5 * $1050 = $5250.
Why others are wrong:
A — This is the value of one ratio part, not the total amount for Trust Y.
B — This is the amount allocated to Trust X (3 * $1050), not Trust Y.
C — This would be the amount if the money were split equally, ignoring the given ratio.
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