Exercise: Exam Question Papers
Questions for: Exam Question Papers
Consider a silicon p-n junction at room temperature having the following parameters:
Doping on the n-side = 1 x 1017 cm-3
Depletion width on the n-side = 0.1 Ξm
Depletion width on the p-side = 1.0 Ξm
Intrinsic carrier concentration = 1.4 x 1014F. cm-1.
Thermal voltage = 26mV
Permittivity of free space = 8.85 x 10-14F. cm-1.
Dielectric constant of silicon = 12. The peak electric field in the device is
Doping on the n-side = 1 x 1017 cm-3
Depletion width on the n-side = 0.1 Ξm
Depletion width on the p-side = 1.0 Ξm
Intrinsic carrier concentration = 1.4 x 1014F. cm-1.
Thermal voltage = 26mV
Permittivity of free space = 8.85 x 10-14F. cm-1.
Dielectric constant of silicon = 12. The peak electric field in the device is
A:
0.15 MV.com-1, directed from p-region to n-region
B:
0.15 MV.com-1, directed from n-region to p-region
C:
1.80 MV.com-1, directed from p-region to n-region
D:
1.80 MV.com-1, directed from n-region to p-region
Answer: B
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Which of the following addressing modes is used in the instruction PUSH B?
A:
Direct
B:
Register
C:
Register Indirect
D:
Immediate
Answer: C
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In the circuit shown below, the op-amp is ideal, the transistor has VBE = 0.6 V and Îē = 150. Decide whether the feedback in the circuit is positive or negative and determine the voltage V at the output of the op-amp
A:
Positive feedback, V = 10 V
B:
Positive feedback, V = 0 V
C:
Negative feedback, V = 5 V
D:
Negative feedback, V = 2 V
Answer: D
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For a message signal m(t) = cos (2pfmt) and the carrier frequency fc, which of the following represents a single side band (SSB) signal?
A:
cos (2pfmt) cos (2pfct)
B:
cos (2pfct)
C:
cos [2p(fc + fm) t]
D:
[1 + cos (2pfmt) cos (2pfct)]
Answer: C
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In the design of a single mode step index optical fiber close to upper cut-off, the single mode operations is NOT preserved if
A:
radius as well as operating wavelength are halved
B:
radius as well as operating wavelength are doubled
C:
radius is halved and operating wavelength is doubled
D:
radius is doubled and operating wavelength is halved
Answer: B
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