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Compare this with
where s = 3.
f1 = y2 + y6 + y11 + y12
and f2 = y1 + yl0 + yl3
f1(m, n, o, p) = (3, 4, 9, 13)
f2(m, n, o, p) = (2, 5, 14)
∴ = Π(2, 3, 4, 5, 9, 13, 14).
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