Exercise: Exam Question Papers

Questions for: Exam Question Papers

A silicon PN junction with no bias have a doping concentration of
Nd = 2 x 1016 cm-3 and Na = 1016 cm-3. The space charge width is:
A:
3.345 x 10-3 cm
B:
3.345 x 10-4 cm
C:
3.345 x 10-5 cm
D:
3.345 x 10-6 cm
Answer: C

w = 3.345 x 10-5 cm.

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Locus of a point Z satisfying the equation arg is:
A:
Straight line with equation y = x - 3
B:
Circle with equation x2 + y2 - 3x + 3y = 0
C:
Hyperbola with equation x2 - y2 - 3x - 3y - 2yx = 0
D:
None of these
Answer: B

Solving this further we will get x2 + y2 - 3x + 3y = 0 which is the equation of circle.

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Time domain equivalent circuit of the figure is
A:
B:
C:
D:
None of the above
Answer: A

In the left hand loop (- i1) enters the dot end while for the right handed loop i2 enters the dot end.

This will make both the M terms at first of + ve sign but as i1 = - ve hence ultimately the M term of right hand loop involving i1 = - ve.

V1 = - L1 + M

V2 = L2 - M .

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The feedback control system shown in the given figure represents
A:
Type 0 system
B:
Type 1 system
C:
Type 2 system
D:
Type 3 system
Answer: D

j gives type of system

j = 3

∴ given system is type 3 system.

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If h1[n] = 3δ[n] + δ[n - 1], h2[n] = 2δ[n] + δ[n - 2]
h3[n] = δ[n] - 3δ[n - 1] + 7δ[n - 4] + 6δ[n - 6]
h[n] = h1[n] * h2[n] + h3[n] * h1[n] has value
A:
{6, 18, 7, 4, 0, - 6, 9}
B:
{9, 0, - 6, 21, 7, 6, 1}
C:
{7, - 1, 3, 1, 7, 0, 6}
D:
{9, - 6, 0, 1, 21, 7, 18, 6}
Answer: D

h1[n] * h2[n] + h3[n] * h1[n] = h1[n] * (h2[n] + h3[n])

Distributive property for convolution,

(h2[n] + h3[n]) = 3δ(n) - 3δ(n - 1) + δ(n - 2) + 7δ(n -4) + 6δ(n - 6) then h1(n) * (h2(n) + h3(n))

{9, - 6, 0, 1, 21, 7, 18, 6}.

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