The given signal can be expressed as multiplication of x₁(t) and x₂(t) as shown below, where A = 2, T/2 = 0.25 ⇒ T = 0.5

∴ x(t) = x₁(t) x x₂(t)

⇒ X(f) = X₁(f) * X₂(f)

Now X₁(f) = [δ(f - f₀) + δ(f + f₀)]

where

and X₂(f) = T . sin c[fT]

⇒ X(f) = [δ(f - f₀) + δ(f + f₀)]

*T. sinc(fT)

= [sinc[T(f - f₀)] + sinc [T(f + f₀)]]

Now, A = 2, T = 0.5

and

⇒ X(f) = 0.5[sin c(0.5(f - 1)) + sinc(0.5(f + 1))].

Given, 5 skilled workers can build a wall in 20 days i.e., 1 skilled worker can the wall build in 100 days

∴ The capacity of each skilled worker is

8 semi-skilled workers can build a wall in 25 days i.e., 1 semi-skilled worker can build a wall in 200 days

∴ The capacity of each semi-skilled worker is

Similarly, The capacity of 1 unskilled worker is

Now, The capacity of 2 skilled + 6 semi-skilled + 5 unskilled workers is

∴ The required numbers of days is 15.

Since microprocessor differentiates between an input or output operation on a port depending upon control signals RD and WR .

Therefore in a microprocessor system same port address can be given to two different input and output ports.

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In a synchro detector, output voltage is proportional to ω(t)

v₀ a ω(t)

So, n must be equal to one.