Exercise: Digital Electronics

Questions for: Digital Electronics

The access time of a word in 4 MB main memory is 100 ms. The access time of a word in a 32 kb data cache memory is 10 ns. The average data cache bit ratio is 0.95. The efficiency of memory access time is
A:
9.5 ns
B:
14.5 ns
C:
20 ns
D:
95 ns
Answer: B

Access time = 0.95 x 10 + 0.05 x 100.

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The number of digits in octal system is
A:
8
B:
7
C:
9
D:
10
Answer: A

The octal system has 8 digits 0 to 7.

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Which of the following is non-saturating?
A:
TTL
B:
CMOS
C:
ECL
D:
Both (a) and (b)
Answer: C

Since it is non-saturating, ECL has low propagation delay.

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In the expression A + BC, the total number of minterms will be
A:
2
B:
3
C:
4
D:
5
Answer: D

The min terms are ABC + ABC + AB C + ABC + ABC.

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For the gate in the given figure the output will be
A:
0 
B:
1
C:
A
D:
A
Answer: D

If A = 0, Y = 1 and A = 1, Y = 0 Therefore Y = A.

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