Exercise: Digital Electronics

Questions for: Digital Electronics

The Boolean function/implemented in the figure using two I/P multiplexers is
A:
ABC + ABC
B:
ABC + AB C
C:
ABC + ABC
D:
ABC + AB C
Answer: A

when B = 1, f1 = ABC

B = 0, f2 = ABC

f = f1 + f2 = ABC + ABC.

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In 2's complement form, - 2 is
A:
1011
B:
1110
C:
1100
D:
1010
Answer: B

A = 1110,

A = 0001,

A + 1 = 0001 + 1 = 0010 = 2

Therefore A = -2.

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A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH
A:
A = B = C = 0
B:
A = B = C = 1
C:
A = B = 1 and C = 0
D:
A = C = 1 and B = 0
Answer: A

NOR gate gives High output when all inputs are Low.

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Which of these is the most recent display device?
A:
LED
B:
LCD
C:
VF
D:
(a) and (c)
Answer: C

VF display can operate at very low voltages, has low power consumption and very long life.

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The number of digits in hexadecimal system
A:
15
B:
16
C:
10
D:
8
Answer: B

It has 16 digits 0 to 15.

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