Exercise: Digital Electronics

Questions for: Digital Electronics

9's complement of 1210 is
A:
2110
B:
8710
C:
7810
D:
7610
Answer: B

99 - 12 = 87.

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The resolution of 4 bit counting ADC is 0.5 volt, for an Analog input of 6.6 volts. The digital output of ADC will be
A:
1011
B:
1101
C:
1100
D:
1110
Answer: B

Digital output of ADC resolution = .

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For the NMOS gate in the given figure, F =
A:
ABCDE
B:
(AB + C) (D + E)
C:
A(B + C) + DE
D:
A + B C + DE
Answer: C

B + C are in parallel and A is in series with this parallel combination, Similarly D + E are in series. Then D, E are in parallel with A, B and C Y = A(B + C) + DE .

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ECL is a saturating logic.
A:
True
B:
False
C:
D:
Answer: B

It is a non-saturating logic. Hence highest speed of operation.

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Inputs A and B of the given figure are applied to a NAND gate. The output is LOW
A:
from 0 to 6
B:
from 0 to 2
C:
from 0 to 1 and 2 to 3
D:
from 1 to 2 and 3 to 4
Answer: C

NAND gate gives Low output if all inputs are High. For other combinations of inputs, output is High.

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