C Preprocessor

Would the following typedef work?
typedef #include l;

A:

Yes

B:

No

C:

D:

Answer: B

Because typedef goes to work after preprocessing.

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Will the program compile successfully?

#include<stdio.h>
#define X (4+Y)
#define Y (X+3)

int main()
{
    printf("%d\n", 4*X+2);
    return 0;
}

A:

Yes

B:

No

C:

D:

Answer: B

Reports an error: Undefined symbol 'X'

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Once preprocessing is over and the program is sent for the compilation the macros are removed from the expanded source code.

A:

True

B:

False

C:

D:

Answer: A

True, After preprocessing all the macro in the program are removed.

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A preprocessor directive is a message from compiler to a linker.

A:

True

B:

False

C:

D:

Answer: B

FALSE

Example: #define symbol replacement

When the preprocessor encounters #define directive, it replaces any occurrence of symbol in the rest of the code by replacement. This replacement can be an statement or expression or a block or simple text.

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The preprocessor can trap simple errors like missing declarations, nested comments or mismatch of braces.

A:

True

B:

False

C:

D:

Answer: B

False, the preprocessor cannot trap the errors, it only replaces the macro with the given expression. But the compiler will detect errors.

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Questions for: C Preprocessor