Exercise: Automatic Control Systems

Questions for: Automatic Control Systems

In the given figure the input is x(t) = A sin ωt. The steady state output y(t) =
A:
A sin (ωt + φ) where φ = tan-1 |G(jω)|
B:
|G(jω)| A sin [ωt + ∠G(jω)]
C:
|G(jω)| A sin [2ωt + ∠G(jω)]
D:
A G(jω) sin [ωt + ∠G(jω)]
Answer: B

The magnitudes A and G(jω) are multiplied and phase angles are added.

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In Bode diagram (log magnitude plot) the factor in the transfer function gives a line having slope
A:
-20 dB per octave
B:
-10 dB per octave
C:
-6 dB per octave
D:
-2 dB per octave
Answer: C

For term the slope is -20 dB/decade or -6 dB/octave because - 20 log 2 = -6 dB.

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For type 2 system, the magnitude and phase angle of the term (jω)2 in the denominator, at ω = 0, are respectively
A:
0 and - 90°
B:
0 and + 90°
C:
infinity and - 180°
D:
infinity and + 180°
Answer: C

If ω = 0, has a magnitude of infinity and phase angle -180°.

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Stepper motors find applications in
A:
X-Y plotters
B:
numerically controlled machining equipment
C:
printers
D:
all of the above
Answer: D

Stepper motors are used in all these applications.

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A lag compensator is essentially a
A:
low pass filter
B:
high pass filter
C:
band pass filter
D:
either (a) or (b)
Answer: A

See transfer function in the equation , β > 1

where t1 = R1C1, t2 = R2C2 and t > 1.

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