Exercise: Automatic Control Systems

Questions for: Automatic Control Systems

The system in the given figure, x(0) = 0 and x (0) = 0, At t = 0 the unit impulse Ξ΄(t) is applied X(s)
A:
B:
C:
D:
Answer: C

Therefore displacement .

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For the system of the given figure the closed loop poles are located at
A:
s = 0 and s = -2
B:
s = 0, s = -l Β± j3
C:
s = -1 Β± j3
D:
s = -2 and s = -1 Β± j3
Answer: C

Transfer function = .

The roots of equation s2 + 2s + 4 = 0 are at -1 Β± 3.

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The open loop transfer function of a unity feedback system is The poles of closed loop system are at
A:
-2, -2
B:
-2, -1
C:
- 2, Β± j 1
D:
- 2, 2
Answer: C

for s2 + 4s + 5 = 0, the roots are - 2 Β± j1.

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A system has 12 poles and 2 zeros. Its high frequency asymptote in its magnitude plot has a slope of
A:
-200 dB/decade
B:
-240 dB/decade
C:
-280 dB/decade
D:
-320 dB/decade
Answer: A

-(12 - 2) 20 or - 200 dB/decade.

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In a second order system Ο‰n = 10 rad/sec and ΞΆ = 0.1, then Ο‰d =
A:
9.1 rad/sec
B:
9.95 rad/sec
C:
9 rad/sec
D:
1 rad/sec
Answer: B

Wd = Ο‰n1 - ΞΆ2 = 10 (1 - 0.01)05 = 9.95 rad/s.

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