Exercise: Analog Electronics

Questions for: Analog Electronics

A half wave diode rectifier uses a diode having forward resistance of 50 ohms. The load resistance is also 50 ohms. Then the voltage regulation is
A:
20%
B:
50%
C:
100%
D:
200%
Answer: C

No load output voltage =

Output voltage at full load = .

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Assuming VCE sat = 0.2 V and Îē = 50, the minimum base current (IB) required to drive the transistor in the given figure to saturation is
A:
56 ΞA
B:
140 ΞA
C:
60 ΞA
D:
3 ΞA
Answer: A

or = Ic = ÎēIB and

2.8 mA

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As the ratio Rf/RL increases the efficiency of a rectifier increases.
A:
True
B:
False
C:
D:
Answer: B

As increases efficiency decreases.

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In the figure, assume the op-amp is to be ideal. The output Vo if the circuit is
A:
10 cos (100t)
B:
C:
D:
Answer: A

KCL at mode one.

... (1)

Applying KCL at node (3)

... (2)

From (1)

V2 = 100 L sin ωt

Put value of V2 in equation (2) and solve for V0 .

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It has been found that in a rectifier circuit with RC filter one RC section reduces ripple by 15%. Two RC sections are used in cascade the reduction in ripple would be
A:
15%
B:
30%
C:
150%
D:
225%
Answer: D

One filter reduces ripple to 0.15 of initial value. The second filter reduces ripple to 0.15 x 0.15 of initial value.

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